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Home » Alexander v Khan moves closer for New York on December 7

Alexander v Khan moves closer for New York on December 7

WBN has learned that the fight is set to go ahead at the Barclays Center in Brooklyn, New York on December 7, with only a few minor points to be ironed out before the fight can be officially announced.

“We did have a fight meeting last week which has brought things a little closer and we hope to make announcement in the next couple weeks. It will likely be New York now,” a Team Khan member told World Boxing News.

Former light-welterweight king Khan, 26, is ready to make his full-blown 147lb debut on the night following his 142lb catchweight win over Julio Diaz in April and faces an in-form Alexander, who is on a four-fight winning streak.

The American, also 26, has defeated the likes of Marcos Maidana, Lucas Matthysse and Randall Bailey since suffering his only loss to Timothy Bradley in 2011, with a second weight world title in gained from the latter success.

The victor of the much-talked about encounter could well be in pole position to meet Floyd ‘Money’ Mayweather on May 3 of next year, with a massive career-high payday giving the world title clash the highest stakes possible.